Check String Has Only Digits

Easy Strings

Check whether a string contains only numeric digits.

Sample input

12345

Sample output

true

Solution

s = "12345"
print(s.isdigit())

const s = "12345";
console.log(/^\d+$/.test(s));

public class Main {
    public static void main(String[] args) {
        String s = "12345";
        boolean allDigits = s.matches("\\d+");
        System.out.println(allDigits);
    }
}

fun main() {
    val s = "12345"
    println(s.isNotEmpty() && s.all { it.isDigit() })
}

let s = "12345"
let allDigits = !s.isEmpty && s.allSatisfy { $0.isNumber }
print(allDigits)

void main() {
  String s = '12345';
  bool allDigits = RegExp(r'^\d+$').hasMatch(s);
  print(allDigits);
}

#include <iostream>
#include <cctype>
using namespace std;

int main() {
    string s = "12345";
    bool allDigits = !s.empty();
    for (char c : s) {
        if (!isdigit(c)) {
            allDigits = false;
            break;
        }
    }
    cout << (allDigits ? "true" : "false") << endl;
    return 0;
}

#include <stdio.h>
#include <ctype.h>
#include <string.h>

int main() {
    char s[] = "12345";
    int allDigits = strlen(s) > 0;
    for (int i = 0; s[i]; i++) {
        if (!isdigit(s[i])) {
            allDigits = 0;
            break;
        }
    }
    printf("%s\n", allDigits ? "true" : "false");
    return 0;
}