Count Digits in a Number

Easy Numbers

Count how many digits a number has.

Sample input

12345

Sample output

Solution

n = 12345
count = 0
while n > 0:
    count += 1
    n //= 10
print(count)

let n = 12345, count = 0;
while (n > 0) {
  count++;
  n = Math.floor(n / 10);
}
console.log(count);

public class Main {
    public static void main(String[] args) {
        int n = 12345, count = 0;
        while (n > 0) {
            count++;
            n /= 10;
        }
        System.out.println(count);
    }
}

fun main() {
    var n = 12345
    var count = 0
    while (n > 0) {
        count++
        n /= 10
    }
    println(count)
}

var n = 12345
var count = 0
while n > 0 {
    count += 1
    n /= 10
}
print(count)

void main() {
  int n = 12345, count = 0;
  while (n > 0) {
    count++;
    n ~/= 10;
  }
  print(count);
}

#include <iostream>
using namespace std;

int main() {
    int n = 12345, count = 0;
    while (n > 0) {
        count++;
        n /= 10;
    }
    cout << count << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 12345, count = 0;
    while (n > 0) {
        count++;
        n /= 10;
    }
    printf("%d\n", count);
    return 0;
}