Count Zeros in a Matrix

Easy Matrix

Count how many zeros are present in a matrix.

Sample input

[[1,0,3],[0,5,0],[7,0,9]]

Sample output

Solution

matrix = [[1, 0, 3], [0, 5, 0], [7, 0, 9]]
count = sum(row.count(0) for row in matrix)
print(count)

const matrix = [[1, 0, 3], [0, 5, 0], [7, 0, 9]];
let count = 0;
for (const row of matrix) {
  for (const x of row) {
    if (x === 0) count++;
  }
}
console.log(count);

public class Main {
    public static void main(String[] args) {
        int[][] matrix = {{1, 0, 3}, {0, 5, 0}, {7, 0, 9}};
        int count = 0;
        for (int[] row : matrix) {
            for (int x : row) {
                if (x == 0) count++;
            }
        }
        System.out.println(count);
    }
}

fun main() {
    val matrix = arrayOf(intArrayOf(1, 0, 3), intArrayOf(0, 5, 0), intArrayOf(7, 0, 9))
    val count = matrix.sumOf { row -> row.count { it == 0 } }
    println(count)
}

let matrix = [[1, 0, 3], [0, 5, 0], [7, 0, 9]]
let count = matrix.reduce(0) { $0 + $1.filter { $0 == 0 }.count }
print(count)

void main() {
  final matrix = [[1, 0, 3], [0, 5, 0], [7, 0, 9]];
  int count = 0;
  for (final row in matrix) {
    for (final x in row) {
      if (x == 0) count++;
    }
  }
  print(count);
}

#include <iostream>
#include <vector>
using namespace std;

int main() {
    vector<vector<int>> matrix = {{1, 0, 3}, {0, 5, 0}, {7, 0, 9}};
    int count = 0;
    for (auto& row : matrix) {
        for (int x : row) {
            if (x == 0) count++;
        }
    }
    cout << count << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int matrix[3][3] = {{1, 0, 3}, {0, 5, 0}, {7, 0, 9}};
    int count = 0;
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            if (matrix[i][j] == 0) count++;
        }
    }
    printf("%d\n", count);
    return 0;
}