Even or Odd

Easy Numbers
Check whether a number is even or odd.

Sample input

7

Sample output

Odd

Solution

n = 7
print("Even" if n % 2 == 0 else "Odd")
const n = 7;
console.log(n % 2 === 0 ? "Even" : "Odd");
public class Main {
    public static void main(String[] args) {
        int n = 7;
        System.out.println(n % 2 == 0 ? "Even" : "Odd");
    }
}
fun main() {
    val n = 7
    println(if (n % 2 == 0) "Even" else "Odd")
}
let n = 7
print(n % 2 == 0 ? "Even" : "Odd")
void main() {
  int n = 7;
  print(n % 2 == 0 ? 'Even' : 'Odd');
}
#include <iostream>
using namespace std;

int main() {
    int n = 7;
    cout << (n % 2 == 0 ? "Even" : "Odd") << endl;
    return 0;
}
#include <stdio.h>

int main() {
    int n = 7;
    printf("%s\n", n % 2 == 0 ? "Even" : "Odd");
    return 0;
}