FizzBuzz

Easy Numbers

Print numbers 1 to 15. For multiples of 3 print "Fizz", for multiples of 5 print "Buzz", and for multiples of both print "FizzBuzz".

Sample input

1 to 15

Sample output

1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz

Solution

for i in range(1, 16):
    if i % 15 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)

for (let i = 1; i <= 15; i++) {
  if (i % 15 === 0) console.log("FizzBuzz");
  else if (i % 3 === 0) console.log("Fizz");
  else if (i % 5 === 0) console.log("Buzz");
  else console.log(i);
}

public class Main {
    public static void main(String[] args) {
        for (int i = 1; i <= 15; i++) {
            if (i % 15 == 0) System.out.println("FizzBuzz");
            else if (i % 3 == 0) System.out.println("Fizz");
            else if (i % 5 == 0) System.out.println("Buzz");
            else System.out.println(i);
        }
    }
}

fun main() {
    for (i in 1..15) {
        when {
            i % 15 == 0 -> println("FizzBuzz")
            i % 3 == 0 -> println("Fizz")
            i % 5 == 0 -> println("Buzz")
            else -> println(i)
        }
    }
}

for i in 1...15 {
    if i % 15 == 0 {
        print("FizzBuzz")
    } else if i % 3 == 0 {
        print("Fizz")
    } else if i % 5 == 0 {
        print("Buzz")
    } else {
        print(i)
    }
}

void main() {
  for (int i = 1; i <= 15; i++) {
    if (i % 15 == 0) {
      print('FizzBuzz');
    } else if (i % 3 == 0) {
      print('Fizz');
    } else if (i % 5 == 0) {
      print('Buzz');
    } else {
      print(i);
    }
  }
}

#include <iostream>
using namespace std;

int main() {
    for (int i = 1; i <= 15; i++) {
        if (i % 15 == 0) cout << "FizzBuzz" << endl;
        else if (i % 3 == 0) cout << "Fizz" << endl;
        else if (i % 5 == 0) cout << "Buzz" << endl;
        else cout << i << endl;
    }
    return 0;
}

#include <stdio.h>

int main() {
    for (int i = 1; i <= 15; i++) {
        if (i % 15 == 0) printf("FizzBuzz\n");
        else if (i % 3 == 0) printf("Fizz\n");
        else if (i % 5 == 0) printf("Buzz\n");
        else printf("%d\n", i);
    }
    return 0;
}