Inverted Star Triangle

Easy Patterns

Print an inverted right-angled triangle of stars with n rows (row i has n-i+1 stars).

Sample input

Sample output

***** **** *** ** *

Solution

n = 5
for i in range(n, 0, -1):
    print("*" * i)

const n = 5;
for (let i = n; i >= 1; i--) {
  console.log("*".repeat(i));
}

public class Main {
    public static void main(String[] args) {
        int n = 5;
        for (int i = n; i >= 1; i--) {
            StringBuilder row = new StringBuilder();
            for (int j = 0; j < i; j++) row.append("*");
            System.out.println(row.toString());
        }
    }
}

fun main() {
    val n = 5
    for (i in n downTo 1) {
        println("*".repeat(i))
    }
}

let n = 5
for i in stride(from: n, through: 1, by: -1) {
    print(String(repeating: "*", count: i))
}

void main() {
  int n = 5;
  for (int i = n; i >= 1; i--) {
    print('*' * i);
  }
}

#include <iostream>
using namespace std;

int main() {
    int n = 5;
    for (int i = n; i >= 1; i--) {
        for (int j = 0; j < i; j++) cout << "*";
        cout << endl;
    }
    return 0;
}

#include <stdio.h>

int main() {
    int n = 5;
    for (int i = n; i >= 1; i--) {
        for (int j = 0; j < i; j++) printf("*");
        printf("\n");
    }
    return 0;
}