Largest Element in an Array

Easy Arrays

Find the maximum value in an array of integers.

Sample input

[3, 7, 2, 9, 4]

Sample output

Solution

arr = [3, 7, 2, 9, 4]
largest = arr[0]
for x in arr:
    if x > largest:
        largest = x
print(largest)

const arr = [3, 7, 2, 9, 4];
let largest = arr[0];
for (const x of arr) {
  if (x > largest) largest = x;
}
console.log(largest);

public class Main {
    public static void main(String[] args) {
        int[] arr = {3, 7, 2, 9, 4};
        int largest = arr[0];
        for (int x : arr) {
            if (x > largest) largest = x;
        }
        System.out.println(largest);
    }
}

fun main() {
    val arr = intArrayOf(3, 7, 2, 9, 4)
    var largest = arr[0]
    for (x in arr) {
        if (x > largest) largest = x
    }
    println(largest)
}

let arr = [3, 7, 2, 9, 4]
var largest = arr[0]
for x in arr where x > largest {
    largest = x
}
print(largest)

void main() {
  List<int> arr = [3, 7, 2, 9, 4];
  int largest = arr[0];
  for (var x in arr) {
    if (x > largest) largest = x;
  }
  print(largest);
}

#include <iostream>
using namespace std;

int main() {
    int arr[] = {3, 7, 2, 9, 4};
    int n = 5, largest = arr[0];
    for (int i = 1; i < n; i++) {
        if (arr[i] > largest) largest = arr[i];
    }
    cout << largest << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int arr[] = {3, 7, 2, 9, 4};
    int n = 5, largest = arr[0];
    for (int i = 1; i < n; i++) {
        if (arr[i] > largest) largest = arr[i];
    }
    printf("%d\n", largest);
    return 0;
}