Power of Two Check

Easy Numbers

Check whether a number is a power of two using bit manipulation.

Sample input

Sample output

true

Solution

n = 16
print(n > 0 and (n & (n - 1)) == 0)

const n = 16;
console.log(n > 0 && (n & (n - 1)) === 0);

public class Main {
    public static void main(String[] args) {
        int n = 16;
        System.out.println(n > 0 && (n & (n - 1)) == 0);
    }
}

fun main() {
    val n = 16
    println(n > 0 && (n and (n - 1)) == 0)
}

let n = 16
print(n > 0 && (n & (n - 1)) == 0)

void main() {
  int n = 16;
  print(n > 0 && (n & (n - 1)) == 0);
}

#include <iostream>
using namespace std;

int main() {
    int n = 16;
    cout << ((n > 0 && (n & (n - 1)) == 0) ? "true" : "false") << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 16;
    printf("%s\n", (n > 0 && (n & (n - 1)) == 0) ? "true" : "false");
    return 0;
}