Print Numbers Divisible by 3 or 5

Easy Loops

Print all numbers from 1 to n that are divisible by 3 or 5.

Sample input

Sample output

3 5 6 9 10 12 15

Solution

n = 15
result = [i for i in range(1, n + 1) if i % 3 == 0 or i % 5 == 0]
print(*result)

const n = 15;
const result = [];
for (let i = 1; i <= n; i++) {
  if (i % 3 === 0 || i % 5 === 0) result.push(i);
}
console.log(result.join(" "));

import java.util.stream.Collectors;
import java.util.stream.IntStream;

public class Main {
    public static void main(String[] args) {
        int n = 15;
        System.out.println(IntStream.rangeClosed(1, n).filter(i -> i % 3 == 0 || i % 5 == 0)
            .mapToObj(String::valueOf).collect(Collectors.joining(" ")));
    }
}

fun main() {
    val n = 15
    val result = (1..n).filter { it % 3 == 0 || it % 5 == 0 }
    println(result.joinToString(" "))
}

let n = 15
let result = (1...n).filter { $0 % 3 == 0 || $0 % 5 == 0 }
print(result.map(String.init).joined(separator: " "))

void main() {
  int n = 15;
  final result = <int>[];
  for (var i = 1; i <= n; i++) {
    if (i % 3 == 0 || i % 5 == 0) result.add(i);
  }
  print(result.join(' '));
}

#include <iostream>
using namespace std;

int main() {
    int n = 15;
    bool first = true;
    for (int i = 1; i <= n; i++) {
        if (i % 3 == 0 || i % 5 == 0) {
            if (!first) cout << " ";
            cout << i;
            first = false;
        }
    }
    cout << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 15, first = 1;
    for (int i = 1; i <= n; i++) {
        if (i % 3 == 0 || i % 5 == 0) {
            if (!first) printf(" ");
            printf("%d", i);
            first = 0;
        }
    }
    printf("\n");
    return 0;
}