Reverse an Array

const arr = [1, 2, 3, 4, 5];
arr.reverse();
console.log(arr.join(" "));

public class Main {
    public static void main(String[] args) {
        int[] arr = {1, 2, 3, 4, 5};
        StringBuilder sb = new StringBuilder();
        for (int i = arr.length - 1; i >= 0; i--) {
            sb.append(arr[i]);
            if (i > 0) sb.append(" ");
        }
        System.out.println(sb.toString());
    }
}

fun main() {
    val arr = intArrayOf(1, 2, 3, 4, 5)
    arr.reverse()
    println(arr.joinToString(" "))
}

var arr = [1, 2, 3, 4, 5]
arr.reverse()
print(arr.map { String($0) }.joined(separator: " "))

void main() {
  List<int> arr = [1, 2, 3, 4, 5];
  var reversed = arr.reversed.toList();
  print(reversed.join(' '));
}

#include <iostream>
#include <algorithm>
using namespace std;

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int n = 5;
    reverse(arr, arr + n);
    for (int i = 0; i < n; i++) {
        cout << arr[i];
        if (i < n - 1) cout << " ";
    }
    cout << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int n = 5;
    for (int i = n - 1; i >= 0; i--) {
        printf("%d", arr[i]);
        if (i > 0) printf(" ");
    }
    printf("\n");
    return 0;
}