Sum of Even Numbers

Easy Numbers

Find the sum of all even numbers from 1 to n.

Sample input

Sample output

Solution

n = 10
total = sum(i for i in range(1, n + 1) if i % 2 == 0)
print(total)

const n = 10;
let total = 0;
for (let i = 1; i <= n; i++) {
  if (i % 2 === 0) total += i;
}
console.log(total);

public class Main {
    public static void main(String[] args) {
        int n = 10, total = 0;
        for (int i = 1; i <= n; i++) {
            if (i % 2 == 0) total += i;
        }
        System.out.println(total);
    }
}

fun main() {
    val n = 10
    var total = 0
    for (i in 1..n) {
        if (i % 2 == 0) total += i
    }
    println(total)
}

let n = 10
var total = 0
for i in 1...n {
    if i % 2 == 0 {
        total += i
    }
}
print(total)

void main() {
  int n = 10, total = 0;
  for (int i = 1; i <= n; i++) {
    if (i % 2 == 0) total += i;
  }
  print(total);
}

#include <iostream>
using namespace std;

int main() {
    int n = 10, total = 0;
    for (int i = 1; i <= n; i++) {
        if (i % 2 == 0) total += i;
    }
    cout << total << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 10, total = 0;
    for (int i = 1; i <= n; i++) {
        if (i % 2 == 0) total += i;
    }
    printf("%d\n", total);
    return 0;
}