Sum of First N Odd Numbers

Easy Loops

Add up the first n odd numbers using a loop.

Sample input

Sample output

Solution

n = 5
total = 0
for i in range(n):
    total += 2 * i + 1
print(total)

const n = 5;
let total = 0;
for (let i = 0; i < n; i++) {
  total += 2 * i + 1;
}
console.log(total);

public class Main {
    public static void main(String[] args) {
        int n = 5, total = 0;
        for (int i = 0; i < n; i++) {
            total += 2 * i + 1;
        }
        System.out.println(total);
    }
}

fun main() {
    val n = 5
    var total = 0
    for (i in 0 until n) {
        total += 2 * i + 1
    }
    println(total)
}

let n = 5
var total = 0
for i in 0..<n {
    total += 2 * i + 1
}
print(total)

void main() {
  int n = 5, total = 0;
  for (var i = 0; i < n; i++) {
    total += 2 * i + 1;
  }
  print(total);
}

#include <iostream>
using namespace std;

int main() {
    int n = 5, total = 0;
    for (int i = 0; i < n; i++) {
        total += 2 * i + 1;
    }
    cout << total << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 5, total = 0;
    for (int i = 0; i < n; i++) {
        total += 2 * i + 1;
    }
    printf("%d\n", total);
    return 0;
}