Sum of Multiples of 3 or 5

Easy Loops

Find the sum of all numbers below n that are multiples of 3 or 5 (classic warm-up).

Sample input

Sample output

Solution

n = 10
total = sum(i for i in range(1, n) if i % 3 == 0 or i % 5 == 0)
print(total)

const n = 10;
let total = 0;
for (let i = 1; i < n; i++) {
  if (i % 3 === 0 || i % 5 === 0) total += i;
}
console.log(total);

public class Main {
    public static void main(String[] args) {
        int n = 10, total = 0;
        for (int i = 1; i < n; i++) {
            if (i % 3 == 0 || i % 5 == 0) total += i;
        }
        System.out.println(total);
    }
}

fun main() {
    val n = 10
    val total = (1 until n).filter { it % 3 == 0 || it % 5 == 0 }.sum()
    println(total)
}

let n = 10
let total = (1..<n).filter { $0 % 3 == 0 || $0 % 5 == 0 }.reduce(0, +)
print(total)

void main() {
  int n = 10, total = 0;
  for (var i = 1; i < n; i++) {
    if (i % 3 == 0 || i % 5 == 0) total += i;
  }
  print(total);
}

#include <iostream>
using namespace std;

int main() {
    int n = 10, total = 0;
    for (int i = 1; i < n; i++) {
        if (i % 3 == 0 || i % 5 == 0) total += i;
    }
    cout << total << endl;
    return 0;
}

#include <stdio.h>

int main() {
    int n = 10, total = 0;
    for (int i = 1; i < n; i++) {
        if (i % 3 == 0 || i % 5 == 0) total += i;
    }
    printf("%d\n", total);
    return 0;
}