Truncate String with Ellipsis

Easy Strings

Truncate a string to a maximum length and append "..." if it was shortened — useful for list titles in mobile UIs.

Sample input

"Hello World", maxLen = 8

Sample output

Hello Wo...

Solution

s = "Hello World"
max_len = 8
print(s if len(s) <= max_len else s[:max_len] + "...")

const s = "Hello World";
const maxLen = 8;
console.log(s.length <= maxLen ? s : s.slice(0, maxLen) + "...");

public class Main {
    public static void main(String[] args) {
        String s = "Hello World";
        int maxLen = 8;
        System.out.println(s.length() <= maxLen ? s : s.substring(0, maxLen) + "...");
    }
}

fun main() {
    val s = "Hello World"
    val maxLen = 8
    println(if (s.length <= maxLen) s else s.substring(0, maxLen) + "...")
}

let s = "Hello World"
let maxLen = 8
if s.count <= maxLen {
    print(s)
} else {
    print(String(s.prefix(maxLen)) + "...")
}

void main() {
  String s = 'Hello World';
  int maxLen = 8;
  print(s.length <= maxLen ? s : s.substring(0, maxLen) + '...');
}

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s = "Hello World";
    int maxLen = 8;
    if ((int) s.size() <= maxLen) {
        cout << s << endl;
    } else {
        cout << s.substr(0, maxLen) << "..." << endl;
    }
    return 0;
}

#include <stdio.h>
#include <string.h>

int main() {
    char s[] = "Hello World";
    int maxLen = 8;
    if ((int) strlen(s) <= maxLen) {
        printf("%s\n", s);
    } else {
        printf("%.*s...\n", maxLen, s);
    }
    return 0;
}